Why 'C' is the default hard disk drive name

Computers have been really important part of our lives. Making our work easy and complete it in no time is the main advantage of computers. In the beginning computers were really expensive and were used by few people. Then with the increase and ease in technology computers became affordable and now-a-days everyone is using computers. Computers are proved as an evolution in our lives.

Though you may be using computers but some of you may not be aware of some hidden facts. If you are using computers daily so here is one simple question for you.

" Do you know why 'C' is the default hard dis drive and not 'A' or 'B'?

Here is the answer:

Hard disk drives became standard since 1980, Before Hard disk drives Floppy disk drivers were used as storage devices. Floppy Disk drives were initial storage devices. They came to existence in 1960's. They came in mainly 2 sizes, 5 1/4" and 3 1/2".

These two floppy disk drives were labelled as Local Disk (A) and Local Disk (B). After the invention of Hard disk , floppy disk of size 8 inch came to existence.Presently Floppy Disk drives and Hard disk drives replace floppy disks.

This is the reason behind 'C' being the default disk drive name. Next drive names are than labelled as D, E etc. DVD drive and USB drive are further named as F, G etc.

Though 'C' is the default drive name but if you want to you can change it to 'A' or 'B' if you have the administrative rights.

Comments

1235. Maximum Profit in Job Scheduling

Hi everyone, Today's post is little bit intriguing to me as it took me some time to get t the solution. I have been out of practice for a bit so I was not able to do it in the DP. I didn't want to copy the code. Though i understood the code after i checked its solution in the discussions. Anyways, i tried to do it with heap and with some thinking I was able to do it and with my surprise It performed real well. I would like to jump to the solution but first I would like to explain a little bit about heaps so you can get better understanding of the code. A heap is like a special type of list where the smallest (or largest) item is always at the front. Think of it like a priority line at a theme park, where the person with the highest priority goes to the front. There are two types of heaps: Min Heap: The smallest item is at the front. It's like standing in a line where the shortest person is always at the front. Max Heap: The largest item is at the front. It's like stand...

1456, Maximum Number of Vowels in a Substring of Given Length

Hi, folks today I am here with an interesting coding problem from Leetcode. *To directly go to the question please click here. So I will walk through the solution. It will be a brute force and an optimized way solution. I will be explaining the optimized way solutions in depth. # Intuition For any substring of length k, we need to find how many vowels are there in it and provide the highest count of all counts of vowels in a substring. Test Case 1 Input k = 2 and s='asjdee' Output - 2 Explanation: As for substring of length k=2, in the string 's' we have 'ee' when the length is k and the vowels count is 2 Test Case 2 Input k=3 and s='aasdiisdwe' Output - 2 Explanation - For all the substrings with length k = 3 we have 'aas' and 'dii' with 2 vowels each in it. Brute Force - Looping (twice) - Gives TLE (Not recommended) # Approach Create a hashmap (dictionary) with all the vowels in it. Loop through the string till len(s)-k element of strin...

2125. Number of Laser Beams in a Bank

Hi Guys, Today is 3 January 2024 and below is the solution for problem of the day So, the question we have is Number of Laser Beams in a Bank . In this we have to find total number of lasers. So just imagine it as we have to find number of lines connecting the dots. so if there are 2 dots. we will have one line, if we have 3 dots we will get 3 lines, and so on... Now relate the above provided example, let's relate this to our problem statement. We have 4 walls, first wall has 3 lasers, second wall has 0 lasers, third wall got 2 lasers and last wall has 1 laser. So as i suggested we need to connect dots so make sure to only join adjacent dots. So lasers from 1 and 3 wall will connect to each other (6 lasers) and wall 3 and 4 will connect to each other (2 lasers). So total of 8 lasers, which is the required output anyways. class Solution : def numberOfBeams ( self , bank : List[ str ]) -> int : val = 0 # Initialize a variable `val` to store th...

TechGen

Search This Blog