Skip to main content

Microsoft to drop the update of Windows 10 S


Microsoft is dropping ‘Windows 10 S ‘and SKU mode in favor of the new S mode. The news is confirmed That it will be done for Windows 10 Home, Pro and Education. The step must be taken in accordance to avoid the confusion among its hardware partners and consumers alike.


Microsoft introduced Windows 10 S late year in May. It was designated as “Streamlined version “ of its Windows 10 operating system. It is a fully functional version of Windows version provided to compete with Google’s Chrome Operating System. Unlike other versions of Windows 10, Windows 10 S didn’t allow users to download apps from third party stores and sites. That was really troublesome. The Surface Laptops were the first commercial device to available to run Windows 10 S. Total fee of $49 is to be provided for upgrading full version so that you can enjoy full functions of Windows 10 S.

Now it looks like Microsoft’s windows 10 S hasn’t got the desired attention which company hoped for. This is the reason that they are introducing new “S Mode” that will e available to OEMs across Windows 10 Home, Pro and Educational SKUs. The S mode will not allow user to download apps from the third party source killing the purpose of having a standalone Windows 10 S.


According to the user review it was noticed that out of those who bought Windows 10 S OS, 40 % were not bothered with the OS and rest 60% changed to Windows 10 Pro within 24 hours of the purchase. This data excludes the Surface Laptop device users. Eventually, it is said that Windows 10 Home users can disable the S mode free of cost. Those with Windows 10 Pro have to pay $49 to enable the S mode on their devices to get full access to Windows 10 Pro.

Comments

Popular posts from this blog

1235. Maximum Profit in Job Scheduling

Hi everyone, Today's post is little bit intriguing to me as it took me some time to get t the solution. I have been out of practice for a bit so I was not able to do it in the DP. I didn't want to copy the code. Though i understood the code after i checked its solution in the discussions. Anyways, i tried to do it with heap and with some thinking I was able to do it and with my surprise It performed real well. I would like to jump to the solution but first I would like to explain a little bit about heaps so you can get better understanding of the code. A heap is like a special type of list where the smallest (or largest) item is always at the front. Think of it like a priority line at a theme park, where the person with the highest priority goes to the front. There are two types of heaps: Min Heap: The smallest item is at the front. It's like standing in a line where the shortest person is always at the front. Max Heap: The largest item is at the front. It's like stand...

1456, Maximum Number of Vowels in a Substring of Given Length

Hi, folks today I am here with an interesting coding problem from Leetcode. *To directly go to the question please click here. So I will walk through the solution. It will be a brute force and an optimized way solution. I will be explaining the optimized way solutions in depth. # Intuition For any substring of length k, we need to find how many vowels are there in it and provide the highest count of all counts of vowels in a substring. Test Case 1 Input k = 2 and s='asjdee' Output - 2 Explanation: As for substring of length k=2, in the string 's' we have 'ee' when the length is k and the vowels count is 2 Test Case 2 Input k=3 and s='aasdiisdwe' Output - 2 Explanation - For all the substrings with length k = 3 we have 'aas' and 'dii' with 2 vowels each in it. Brute Force - Looping (twice) - Gives TLE (Not recommended) # Approach Create a hashmap (dictionary) with all the vowels in it. Loop through the string till len(s)-k element of strin...

2125. Number of Laser Beams in a Bank

Hi Guys, Today is 3 January 2024 and below is the solution for problem of the day So, the question we have is Number of Laser Beams in a Bank .  In this we have to find total number of lasers. So just imagine it as we have to find number of lines connecting the dots.  so if there are 2 dots. we will have one line, if we have 3 dots we will get 3 lines, and so on... Now relate the above provided example, let's relate this to our problem statement.   We have 4 walls, first wall has 3 lasers, second wall has 0 lasers, third wall got 2 lasers and last wall has 1 laser. So as i suggested we need to connect dots so make sure to only join adjacent dots. So lasers from 1 and 3 wall  will connect to each other (6 lasers) and wall 3 and 4 will connect to each other (2 lasers). So total of 8 lasers, which is the required output anyways. class Solution : def numberOfBeams ( self , bank : List[ str ]) -> int : val = 0 # Initialize a variable `val` to store th...